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Help!! I need answers now!! Equations of work, potiential energy, kinetic energy, power, and force.?
Can you guys check my homework please?
1. You lift a bag of mulch 1.2 meters and carry it 10m to the garden. How much work is being done?
2. It took a 500N ballerina a force of 250J to lift herself upward through the air. She land 2.5m to the left after her jump. How high did she jump?
3. A people conveyor-belt moves a 600N person a distance of 100 meters thought the airport. How much work is being done?
4. A 600N person lifts a 100N bag an upward distance of 1 meter. They traveled 100m by riding a conveyor-belt. How much work was done in this situation?
1. 504 joules 2. 0.5m 3. 60,000joules 4. 70,700 joules
My teacher is absent and our entire class is failing assignments. I'm a A student so I don't want my grade to be hurt. I'm am having trouble with questions similar to number 2. I believe you use the potintial energy equation but I'm not sure. If you could explain what equation to use that would be great ty!! 10 points to who can explain it and save me my A in physics.
1. Insufficient data. You need to know the weight of the mulch. The distance it was carried is irrelevant; only the lifting does work.
2. 250 J is an energy, not a force. This is the kinetic energy of the jump, hence 250 = 500/9.8 v^2/2, where v is the velocity of the leap. Assume that the launch angle was 45 degrees (optimal); this splits the velocity into two components, each 1/sqrt(2) of the original. A shortcut is now available; half the kinetic energy was the vertical component, so the height if the jump is 250 = m g h, or 250 = 500 h, so h is 0.5 meters. However, if h is 0.5 meters, the maximum horizontal distance is only 2 meters, so the problem as stated has no solution.
3. None.
4. 100 newtons x 1 meter = 100 joules.
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